Hello everybody.
Apologies for my intrusion on your forum but I really am in need of some advice so I decided to ask my question to the MSX community.
I bought a Quickshot V joystick and after doing some research on the internet I realised that it is a joystick designed for the MSX system. However, I plan to use it with a Zx spectrum 48K.( It kind works with some kempston interfaces but not with others.)
My main doubt is how it is supposed to work in the first place with the MSX, I mean precisely the fire buttons.
There are three triggers but two are red so I assume they are the same.
The red and yellow ones on the stick handle are diferrent and should work as manual fire buttons, right?
And what about the big red flat pad on the body? Is it supposed to work as an 'auto-fire' fire button, simulating various presses with only one? I ask this because I opened the joystick and saw some transistors and resistors that make a circuit but I didn't understand what it is supposed to do. This circuit requires the +5Volts of pin 5 of the MSX to work?
I have looked at the MSX Joystick port pinout and since it uses +5V on pin 5 does that mean it reads voltage drops from +5 to 0 to detect button presses?
Assuming I am right, would it be possible to use this joystick on a spectrum, even if looses the 2nd fire button (yellow) but keeping both manual and 'auto-fire' red fire buttons?
Must I change the wiring to match pin-out compatibility between systems?
Sorry for all these questions. I would very much appreciate any help.
Thanks in advance.