the msx vdp require two bytes to set the vram ptr.
What happen if, the vramptr = 0x1000
and one does
out (0x99),80
out (0x98),byte to write
Does the next byte be written on 0x1080 ?
I ask this because on the sms vdp seem to work. Because the vdp are similar i'm asking myself if can work.
I cannot test on the real hw, and i'm not sure that emulators emulate this.....
anyone know?
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