The circumference of a circle, with centre O, is divided into three arcs APB, BQC and CRA such that : $\frac{arcAPB}{2}=\frac{arcBQC}{2}=\frac{arcCRA}{2}\phantom{\rule{0ex}{0ex}}Find\angle BOC.$ Share with your friends Share 2 Varen Atray answered this 2COD= -7 View Full Answer Hitesh Kothari answered this Answering -4